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Question: Contains carbon that are \(s{p^2}\) hybridized: A. \({C_2}{H_6}\) B. \({C_2}{H_4}\) C. \({C_2...

Contains carbon that are sp2s{p^2} hybridized:
A. C2H6{C_2}{H_6}
B. C2H4{C_2}{H_4}
C. C2H2{C_2}{H_2}
D. C2H5OH{C_2}{H_5}OH
E. C3H8{C_3}{H_8}

Explanation

Solution

In order to answer this question, you must recall the concepts of Hybridization and Chemical Bonding. Use the formula or the concepts for finding the sp2s{p^2} Hybridization among the given option and choose the correct option.

Complete step by step solution:
Hybridization is defined as the concept of mixing two atomic orbitals with the same energy levels to give a degenerated new type of orbitals. This intermixing is based on quantum mechanics. The atomic orbitals of the same energy level can only take part in hybridization and both full-filled and half-filled orbitals can also take part in this process, provided they have equal energy.
Hybridization = No. of sigma bonds + No. of lone pairs\text{Hybridization = No. of sigma bonds + No. of lone pairs}
On substituting the values for given compound we get
C2H6{C_2}{H_6} the carbon is sp3s{p^3} having hybridization number 4.
C2H4{C_2}{H_4} the carbon is sp2s{p^2} having hybridization number 3.
C2H2{C_2}{H_2} the carbon is sp2s{p^2} having hybridization number 2.
C2H5OH{C_2}{H_5}OH the carbon is sp2s{p^2} having hybridization number 4.
C3H8{C_3}{H_8} the carbon is sp2s{p^2} having hybridization number 4.

In ethene there are three sigma bonds and zero lone pair therefore the hybridization number is 3 hence the carbon atom is. sp2s{p^2} hybridization is observed when one s and two p orbitals of the same shell of an atom mix to form 3 equivalent orbital.
The new orbitals formed are called sp2s{p^2} hybrid orbitals. Ethene or C2H4{C_2}{H_4}​ is sp2s{p^2} hybridized. Here, each carbon atom has three sp2s{p^2} hybridized orbitals. Two of them form sigma bonds with two Hydrogen atoms. While, the other forms another sigma bond with the second carbon atom.
Hence, we got the required answer i.e. C2H4{C_2}{H_4}

So, the correct answer is Option B.

Note: Ethene C2H4{C_2}{H_4} has a double bond between the carbons. In this case, carbon will sp2s{p^2} hybridize; in sp2s{p^2} hybridization, the 2s orbital mixes with only two of the three available 2p orbitals, forming a total of three sp hybrid orbitals with one p-orbital remaining. The three hybridized orbitals explain the three sigma bonds that each carbon forms.