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Question: Containers \(\frac{T_{1}}{2P_{1}T_{2}}\) and \(\frac{2P_{1}T_{2}}{T_{1} + T_{2}}\) have same gases. ...

Containers T12P1T2\frac{T_{1}}{2P_{1}T_{2}} and 2P1T2T1+T2\frac{2P_{1}T_{2}}{T_{1} + T_{2}} have same gases. Pressure, volume and temperature of 2p1T1+T2\frac{2p_{1}}{T_{1} + T_{2}} are all twice that of H2H_{2} then the ratio of number of molecules of =6.02×1021= 6.02 \times 10^{21} and (vˉ)(\bar{v}) are

A

1 : 2

B

2

C

1 : 4

D

4

Answer

2

Explanation

Solution

According to gas law

20×15020 \times \frac{1}{50}, 50×12050 \times \frac{1}{20}

1×120×501 \times \frac{1}{20} \times 50; 273oC\mathbf{27}\mathbf{3}^{\mathbf{o}}\mathbf{C}

0oC0^{o}C; 0oC\mathbf{0}^{\mathbf{o}}\mathbf{C}