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Question: Construct the circumcircle and incircle of an equilateral \(\Delta ABC\) with side 6cm and center \(...

Construct the circumcircle and incircle of an equilateral ΔABC\Delta ABC with side 6cm and center OO. Find the ratio of radii of circumcircle and incircle.

Explanation

Solution

Hint: Draw a perpendicular bisector on the equilateral triangle which divides the sides of the equilateral triangle into two equal parts. Take their intersection point to draw a circumcircle and incircle. Now use trigonometric ratios in two different triangles for values of in-radius and circum-radius.

Complete step-by-step answer:

The pictorial representation of the given problem is shown above.
The equilateral triangle ABC with side 6 cm has a circumcircle and an incircle with center O and radii r1{r_1} and r2{r_2} respectively.
OB=r1cm, OD=r2cm\Rightarrow OB = {r_1}cm,{\text{ }}OD = {r_2}cm
AE and CD are the perpendicular bisector of BC and AB respectively.
BE=CE=BD=AD=62=3cm\Rightarrow BE = CE = BD = AD = \dfrac{6}{2} = 3cm
Since, FB is the bisector of ABC\angle ABC
FBC=FBA=6002=300\Rightarrow \angle FBC = \angle FBA = \dfrac{{{{60}^0}}}{2} = {30^0}
Because in equilateral triangle all angles are equal which is 600{60^0}
Now, in ΔOBE, cos300 = BEOB=3r1\Delta OBE,{\text{ cos3}}{{\text{0}}^0}{\text{ = }}\dfrac{{BE}}{{OB}} = \dfrac{3}{{{r_1}}}
As we know cos300=32{\text{cos3}}{{\text{0}}^0} = \dfrac{{\sqrt 3 }}{2}
r1=3cos300=332=63cm\Rightarrow {r_1} = \dfrac{3}{{\cos {{30}^0}}} = \dfrac{3}{{\dfrac{{\sqrt 3 }}{2}}} = \dfrac{6}{{\sqrt 3 }}cm
Now in ΔOBD, tan300 = ODBD=r23\Delta OBD,{\text{ tan3}}{{\text{0}}^0}{\text{ = }}\dfrac{{OD}}{{BD}} = \dfrac{{{r_2}}}{3}
As we know tan300=13{\text{tan3}}{{\text{0}}^0} = \dfrac{1}{{\sqrt 3 }}
r2=3tan300=3(13)=3cm\Rightarrow {r_2} = 3\tan {30^0} = 3\left( {\dfrac{1}{{\sqrt 3 }}} \right) = \sqrt 3 cm
Now you have to calculate the ratio of radii circumcircle to incircle
r1r2=633=63×3=63=2cm\dfrac{{{r_1}}}{{{r_2}}} = \dfrac{{\dfrac{6}{{\sqrt 3 }}}}{{\sqrt 3 }} = \dfrac{6}{{\sqrt 3 \times \sqrt 3 }} = \dfrac{6}{3} = 2cm
So, the required ratio of the radii is 2 cm.

Note: In such types of question first draw the pictorial representation of the given problem, then draw the perpendicular bisectors on the triangle which divide its sides into two equal parts, then apply basic trigonometric property and calculate the radii of the two circles, then divide them we will get the required answer.