Question
Question: Construct the circumcircle and incircle of an equilateral \(\Delta ABC\) with side 6cm and center \(...
Construct the circumcircle and incircle of an equilateral ΔABC with side 6cm and center O. Find the ratio of radii of circumcircle and incircle.
Solution
Hint: Draw a perpendicular bisector on the equilateral triangle which divides the sides of the equilateral triangle into two equal parts. Take their intersection point to draw a circumcircle and incircle. Now use trigonometric ratios in two different triangles for values of in-radius and circum-radius.
Complete step-by-step answer:
The pictorial representation of the given problem is shown above.
The equilateral triangle ABC with side 6 cm has a circumcircle and an incircle with center O and radii r1 and r2 respectively.
⇒OB=r1cm, OD=r2cm
AE and CD are the perpendicular bisector of BC and AB respectively.
⇒BE=CE=BD=AD=26=3cm
Since, FB is the bisector of ∠ABC
⇒∠FBC=∠FBA=2600=300
Because in equilateral triangle all angles are equal which is 600
Now, in ΔOBE, cos300 = OBBE=r13
As we know cos300=23
⇒r1=cos3003=233=36cm
Now in ΔOBD, tan300 = BDOD=3r2
As we know tan300=31
⇒r2=3tan300=3(31)=3cm
Now you have to calculate the ratio of radii circumcircle to incircle
r2r1=336=3×36=36=2cm
So, the required ratio of the radii is 2 cm.
Note: In such types of question first draw the pictorial representation of the given problem, then draw the perpendicular bisectors on the triangle which divide its sides into two equal parts, then apply basic trigonometric property and calculate the radii of the two circles, then divide them we will get the required answer.