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Question: Construct a \[2 \times 2\] matrix \[A\] \[ = \left[ {{a_{ij}}} \right]\] such that \[{a_{ij}} = i + ...

Construct a 2×22 \times 2 matrix AA =[aij] = \left[ {{a_{ij}}} \right] such that aij=i+2j{a_{ij}} = i + 2j.

Explanation

Solution

A 2×22 \times 2matrix is a matrix containing two rows and two columns. Now using the given relation, i.e. aij=i+2j{a_{ij}} = i + 2j, substitute the values of i,ji,j and find the elements . Finally arrange the elements in the form of a matrix.

Complete step by step solution:
A matrix is an arrangement of variables or constants in rows and columns enclosed in square brackets. The order of a matrix denotes the number of rows and columns in it. The order of any matrix is denoted by m×nm \times n where mmdenotes the number of rows and nn denotes the number of columns. The position of elements of any matrix are generally denoted by aij{a_{ij}}, where ii represents the row number and jj the column number.
The matrix to be constructed is a 2×22 \times 2 matrix, so it has two rows and two columns.
Now a11{a_{11}} is the element of the first row and first column.
a12{a_{12}} is the element of the first row and second column.
a21{a_{21}} is the element of the second row and first column.
a22{a_{22}} is the element of the second row and second column.
According to the given relation aij=i+2j{a_{ij}} = i + 2j:
a11{a_{11}} == 1+2=31 + 2 = 3
a12=1+4=5{a_{12}} = 1 + 4 = 5
a21=2+2=4{a_{21}} = 2 + 2 = 4
a22=2+4=6{a_{22}} = 2 + 4 = 6
Hence arranging this elements in the form of a 2×22 \times 2 matrix:

{{a_{11}}}&{{a_{12}}} \\\ {{a_{21}}}&{{a_{22}}} \end{array}} \right]$$ **$$ \Rightarrow A = \left[ {\begin{array}{*{20}{c}} 3&5 \\\ 4&6 \end{array}} \right]$$** **Note:** Students can make a mistake in understanding the position of the elements of the matrix. It must be carefully observed and always remember that $$i$$ represents the row and $$j$$ the column number respectively. Also note that for the order of the matrix if $$m = n$$ then the matrix is called a square matrix.