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Question: Consider two vectors \({\overset{\rightarrow}{F}}_{1} = 2\widehat{i} + 5\widehat{k}\) and \({\overse...

Consider two vectors F→1=2i^+5k^{\overset{\rightarrow}{F}}_{1} = 2\widehat{i} + 5\widehat{k} and F→2=3j^+4k^.{\overset{\rightarrow}{F}}_{2} = 3\widehat{j} + 4\widehat{k}. The magnitude of the scalar product of these vectors is

A

20

B

23

C

5335\sqrt{33}

D

26

Answer

26

Explanation

Solution

F→1.F→2=(2j^+5k^)(3j^+4k^){\overrightarrow{F}}_{1}.{\overrightarrow{F}}_{2} = (2\widehat{j} + 5\widehat{k})(3\widehat{j} + 4\widehat{k})

=6+20=20+6=26= 6 + 20 = 20 + 6 = 26