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Question

Physics Question on Gravitation

Consider two solid spheres of radii R,=1m,R2=2mR, = 1m, \,R_2 = 2m and masses M1M_1 and M2M_2, respectively. The gravitational field due to sphere (1) and (2) are shown. The value of m1m2\frac{m_{1}}{m_{2}} is :

A

23\frac{2}{3}

B

16\frac{1}{6}

C

12\frac{1}{2}

D

13\frac{1}{3}

Answer

16\frac{1}{6}

Explanation

Solution

Gravitational field on the surface of a solid
sphere Ig=GMR2I_{g}=\frac{GM}{R^{2}}
By the graph
GM1(1)2=2\frac{GM_{1}}{\left(1\right)^{2}}=2
and GM2(2)2=3\frac{GM_{2}}{\left(2\right)^{2}}=3
On solving
M1M2=16\frac{M_{1}}{M_{2}}=\frac{1}{6}