Solveeit Logo

Question

Question: Consider two infinitely large plane parallel conducting plates as shown below. The plates are unifor...

Consider two infinitely large plane parallel conducting plates as shown below. The plates are uniformly charged with a surface charge density and . The force experienced by a point charge +q placed at the mid point between two plates will be:

Answer

qσϵ0\frac{q\sigma}{\epsilon_0}

Explanation

Solution

The electric field between two infinitely large parallel conducting plates with surface charge densities +σ+\sigma and σ-\sigma on their inner surfaces is E=σϵ0E = \frac{\sigma}{\epsilon_0}. This is derived by superimposing the fields from each plate: E1=σ2ϵ0E_1 = \frac{\sigma}{2\epsilon_0} (away from positive plate) and E2=σ2ϵ0E_2 = \frac{\sigma}{2\epsilon_0} (towards negative plate). Both fields add up in the same direction. The force on a point charge +q in this field is F=qEF = qE. Therefore, F=q(σϵ0)F = q \left(\frac{\sigma}{\epsilon_0}\right).