Solveeit Logo

Question

Physics Question on kinetic theory

Consider two ideal diatomic gases AA and BB at some temperature TT. Molecules of the gas A are rigid , and have an mass mm. Molecules of the gas BB have an additional vibrational mode, and have a mass m4.\frac{m}{4}. The ratio of the specific heats (CVA(C^{A}_{V} and CVB)C^{B}_{V}) of gas AA and BB, respectively is :

A

5:09

B

7:09

C

3:05

D

5:07

Answer

5:07

Explanation

Solution

Degree of freedom of a diatomic molecule if vibration is absent =5= 5
Degree of freedom of a diatomic molecule if vibration is present =7= 7
CvA=fA2R=52R&CvB=fB2R=72R\therefore C^{A}_{v}=\frac{f_{A}}{2} R=\frac{5}{2} R \,\&\,C^{B}_{v}=\frac{f_{B}}{2} R=\frac{7}{2}R
CvACvB=57\therefore \frac{C^{A}_{v}}{C^{B}_{v}}=\frac{5}{7}