Question
Question: Consider three sets A, B, C such that A = {2, 3}, B = {4, 5} and C = {5, 6}. Find, (i) \(A\times \...
Consider three sets A, B, C such that A = {2, 3}, B = {4, 5} and C = {5, 6}. Find,
(i) A×(B∩C)
(ii) (A×B)∪(B×C)
Solution
Hint: For any two sets A and B, the intersection of the two sets A and B (denoted by A∩B) can be found by forming a set which contains the common elements of set A and set B. The cross product of two sets A and B (denoted by A×B) is given by pairing each element of set A with each element of set B. Also, the union of the two sets A and B (denoted by A∪B) is the set of elements which are in set A, in set B, or in both set A and set B. Using this, we can solve this question.
Complete step by step solution:
In the question, we are given three sets A, B, C such that A = {2, 3}, B = {4, 5} and C = {5, 6}.
(i) In this part, we are required to find A×(B∩C).
The intersection of the two sets B and C (denoted by B∩C) can be found by forming a set which contains the common elements of set B and set C. So, we can say,
B∩C = {5}
The cross product of two sets A and B∩C (denoted by A×(B∩C)) is given by pairing each element of set A with each element of set B∩C.
2,3×5 (2,5),(3,5) ⇒A×(B∩C)=⇒A×(B∩C)=
(ii) In this part, we are required to find (A×B)∪(B×C).
The cross product of two sets A and B (denoted by A×B) is given by pairing each element of set A with each element of set B.
⇒A×B=(2,4),(2,5),(3,4),(3,5)
Similarly, we can find B\times C=\left\\{ \left( 4,5 \right),\left( 4,6 \right),\left( 5,5 \right),\left( 5,6 \right) \right\\}.
We have to find the union of the above to obtain cross products which are given by forming a set of elements in set A×B, or in set B×C, or in both the sets.
So, \left( A\times B \right)\cup \left( B\times C \right)=\left\\{ \left( 2,4 \right),\left( 2,5 \right),\left( 3,4 \right),\left( 3,5 \right),\left( 4,5 \right),\left( 4,6 \right),\left( 5,5 \right),\left( 5,6 \right) \right\\}.
Note: It is an easy question which can be done by the basic knowledge of set theory. The only possibility of error in this question is that if one misreads the question. There is a possibility that one may read the union sign as intersection sign or vice versa which may lead us to an incorrect answer.