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Question

Question: Consider the two insulating sheets with thermal resistances R<sub>1</sub> and R<sub>2</sub> as shown...

Consider the two insulating sheets with thermal resistances R1 and R2 as shown in figure. The temperature q is –

A

θ1θ2R1R2(θ1+θ2)(R1+R2)\frac{\theta_{1}\theta_{2}R_{1}R_{2}}{(\theta_{1} + \theta_{2})(R_{1} + R_{2})}

B

θ1R1+θ2R2R1+R2\frac{\theta_{1}R_{1} + \theta_{2}R_{2}}{R_{1} + R_{2}}

C

(θ1+θ2)R1R2R12+R22\frac{(\theta_{1} + \theta_{2})R_{1}R_{2}}{R_{1}^{2} + R_{2}^{2}}

D

θ1R2+θ2R1R1+R2\frac{\theta_{1}R_{2} + \theta_{2}R_{1}}{R_{1} + R_{2}}

Answer

θ1R2+θ2R1R1+R2\frac{\theta_{1}R_{2} + \theta_{2}R_{1}}{R_{1} + R_{2}}

Explanation

Solution

H1 = H2 or θ1θR1\frac{\theta_{1}–\theta}{R_{1}} = θθ2R2\frac{\theta –\theta_{2}}{R_{2}} \ q =θ1R2+θ2R1R1+R2\frac{\theta_{1}R_{2} + \theta_{2}R_{1}}{R_{1} + R_{2}}