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Question

Physics Question on laws of motion

Consider the system shown in figure. The pulley and the string are light and all the surfaces are frictionless. The tension in the string is (take g = 10 m s)

A

0 N

B

1 N

C

2 N

D

5 N

Answer

5 N

Explanation

Solution

If a is acceleration of m, then from fig. m2gT=m2a...(i)m_{2}g-T=m_{2}a\quad\quad\quad\quad\quad\quad\quad...\left(i\right) and T =m1a=1a...(ii)=m_{1}a=1a\quad\quad\quad\quad\quad\quad...\left(ii\right) From (i),m2gT=m2a\left(i\right), m_{2} g - T = m_{2}a 1 g - m1_{1}a = m2_{2}a 1 g = (m1+m2)a=(1+1)a\left(m_{1} + m_{2}\right)a = \left(1 + 1\right)a a=g2=102=5ms2a=\frac{g}{2}=\frac{10}{2}=5m s^{-2} T=m1a=1×\therefore\quad T=m_{1}a=1 \times 5 = 5 N