Question
Question: Consider the statements. Statement-1: The digits A, B, and C are such that the three digit numbers ...
Consider the statements.
Statement-1: The digits A, B, and C are such that the three digit numbers A88, 6B8, 86C are divisible by 72, then the determinant A886B886C is divisible by 288.
Statement-2: A = B = C

Statement-1 is true, Statement-2 is true; Statement-2 is a correct explanation for Statement-1
Statement-1 is true, Statement-2 is true; Statement-2 is not a correct explanation for Statement-1
Statement-1 is true, Statement-2 is false
Statement-1 is false, Statement-2 is true
C
Solution
Explanation:
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Divisibility Rules:
- A number is divisible by 72 if it is divisible by both 8 and 9.
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Finding A, B, and C:
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A88 divisible by 8: 88 is divisible by 8, so A can be any digit from 1 to 9 initially.
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6B8 divisible by 8: 600 + 10B + 8 must be divisible by 8. Since 608 is divisible by 8, 10B must be divisible by 8, implying B must be a multiple of 4. Possible values for B are 0, 4, 8.
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86C divisible by 8: 800 + 60 + C must be divisible by 8. Since 800 is divisible by 8, 60 + C must be divisible by 8. The only digit C for which 60+C is divisible by 8 is C=4.
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A88 divisible by 9: A + 8 + 8 = A + 16. For A+16 to be divisible by 9, A must be 2.
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6B8 divisible by 9: 6 + B + 8 = B + 14. For B+14 to be divisible by 9, B must be 4.
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86C divisible by 9: 8 + 6 + C = C + 14. For C+14 to be divisible by 9, C must be 4.
Therefore, A = 2, B = 4, and C = 4.
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Evaluating the Determinant:
Substitute A=2, B=4, C=4 into the determinant:
D=288648864
D=2(4×4−6×8)−6(8×4−6×8)+8(8×8−4×8)
D=2(16−48)−6(32−48)+8(64−32)
D=2(−32)−6(−16)+8(32)
D=−64+96+256=288
Since 288 is divisible by 288, Statement-1 is true.
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Statement-2 Analysis:
Statement-2 says A = B = C. However, A = 2, B = 4, C = 4. Therefore, Statement-2 is false.
Conclusion: Statement-1 is true, and Statement-2 is false.