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Question: Consider the situation shown in figure. Water \(\left( \mu _ { w } = \frac { 4 } { 3 } \right)\) is ...

Consider the situation shown in figure. Water (μw=43)\left( \mu _ { w } = \frac { 4 } { 3 } \right) is filled in a breaker upto a height of 10 cm. A plane mirror fixed at a height of 5 cm from the surface of water. Distance of image from the mirror after reflection from it of an object O at the bottom of the beaker is

A

15 cm

B

12.5 cm

C

7.5 cm

D

10 cm

Answer

12.5 cm

Explanation

Solution

From figure it is clear that object appears to be raised by

Hence distance between mirror and O=5+7.5=12.5 cmO ^ { \prime } = 5 + 7.5 = 12.5 \mathrm {~cm}

So final image will be formed at 12.5 cm behind the plane mirror.