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Question: Consider the set up shown in figure. The source S is \(\frac{d}{2}\)distance below the optical axis ...

Consider the set up shown in figure. The source S is d2\frac{d}{2}distance below the optical axis and the optical axis is equal distance below the central line. The separation between slits is d. The position of the central maxima on the screen is : [Assume D <<< d]

A

Dd2f\frac{Dd}{2f}

B

Ddf\frac{Dd}{f}

C

Dd3f\frac{Dd}{3f}

D

Dd5f\frac{Dd}{5f}

Answer

Dd2f\frac{Dd}{2f}

Explanation

Solution

Dx = AS1 + S1P – S2P = 0

= d sin q _ dxD\frac{dx}{D} = 0

d × d2f\frac{d}{2f}=dxD\frac{dx}{D}

x =Dd2f\frac{Dd}{2f}