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Question

Chemistry Question on p -Block Elements

Consider the sequence of oxides : Na2O,SiO2Na _{2} O , SiO _{2}, P4O10P _{4} O _{10}. Which factor decreases from Na2ONa _{2} O to SiO2SiO _{2} and also from SiO2SiO _{2} to P4O10P _{4} O _{10} ?

A

Covalent character

B

Melting point

C

pH when mixed with water

D

Solubility in aqueous alkali

Answer

pH when mixed with water

Explanation

Solution

Na2ONa _{2} O is a basic oxide and reacts with water to give NaOHNaOH so that its pHpH is higher than both SiO2SiO _{2} and P4O10P _{4} O _{10}. Both SiO2SiO _{2} and P4O10P _{4} O _{10} are acidic oxides but SiO2SiO _{2} is insoluble while P4O10P_{4} O_{10} reacts with water to give H3PO4H _{3} PO _{4}. Thus, for P4O10,pHP _{4} O _{10}, pH when mixed with water is lower than that of SiO2SiO _{2}.