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Question: Consider the reactions given below. On the basis of these reactions find out which of the algebraic ...

Consider the reactions given below. On the basis of these reactions find out which of the algebraic relations given in options (1) to (4) is correct?

(i) C(g)+4H(g)→CH4(g);ΔrH=xkJmol−1C_{(g)} + 4H_{(g)} \rightarrow CH_{4(g)};\Delta_{r}H = xkJmol^{- 1}

(ii) C(graphite),+2H2(g)→CH4(g);ΔrH=ykJmol−1C_{(graphite),} + 2H_{2(g)} \rightarrow CH_{4(g)};\Delta_{r}H = ykJmol^{- 1}

A

x = y

B

x = 2y

C

x > y

D

x < y

Answer

x > y

Explanation

Solution

: In eqn (i), no bond is being broken while in eqn (ii), 2H –H bonds are broken. So, in eqn (ii) some of the energy is used up to break up to break the bonds. Thus, x > y.