Question

Consider the reaction:VO + Fe2O3 → FeO + V2O5Calculate the weight of FeO produced from 2 g of VO and 5.75 g of Fe2O3.[Take atomic weights of V and Fe to be 51 u and 56 u, respectively.]

• A. (A) 5.17 g
• B. (B) 5.75 g
• C. (C) 6.76 g
• D. (D) 7.19 g

Answer 1

Answer: (A)

(A) 5.17 g

Answer 2

Explanation:
Balanced equation:2VO+3Fe2O3→6FeO+V2O5Moles before reaction: nVO=267=0.0298nFe2O3=5.75160=0.0359Amount of Fe2O3 required by 0.0298g of VO=32×0.0298=0.04478Therefore, Fe2O3 is the limiting reagent.nFeOformed=2×nFe2O3used=2×0.0359=0.0718Weight of FeO produced =0.0718×72=5.169g