Question

Consider the reaction : (T = 298 K)

$\text{C}\text{l}_{2}(g)\text{ + 2Br¯}(\text{aq})\text{ 2Cl¯ }(\text{aq})\text{ + B}\text{r}_{2}\ (\text{aq.})$ The emf of the cell, when $\lbrack\text{Cl¯}\rbrack\text{ = }\lbrack\text{B}\text{r}_{2}\rbrack\text{ = }\lbrack\text{Br¯}\rbrack\text{ = 0.01M }$and $\text{C}\text{l}_{2}$gas is at 1 atm pressure, will be :

(E⁰ for the above reaction is = 0.29 volt)

• A. 0.54 volt
• B. 0.35 volt
• C. 0.24 volt
• D. –0.29 volt

Answer 1

Answer: (B)

0.35 volt

Answer 2

Ecell = 0.29 –$\frac{0.059}{2}$ log$\frac{0.01 \times (0.01)^{2}}{(0.01)^{2} \times 1}$or Ecell

= 0.35 volt