Question
Question: Consider the nuclear reaction X<sup>200</sup>® A <sup>110</sup> + B<sup>80</sup>. If the binding ene...
Consider the nuclear reaction X200® A 110 + B80. If the binding energy per nucleon for X, A and B are 7.4 MeV, 8.2 MeV and 8.1 MeV respectively, then the energy released in the reaction-
A
70 MeV
B
200 MeV
C
190 MeV
D
10 MeV
Answer
70 MeV
Explanation
Solution
For X : energy = 200 × 7.4 = 1480 MeV
For A : energy = 110 × 8.2 = 902 MeV
For B : energy = 80 × 8.1 = 648 MeV
\ Energy released = (902 + 648) – 1480
= 1550 – 1480
= 70 MeV