Question

Consider the nitration of benzene using mixed conc. ${H_2SO_4}$ and ${HNO_3}$. If a large amount of ${KHSO_4}$ is added to the mixture, the rate of nitration will be :

• A. slower
• B. uncharged
• C. doubled
• D. faster

Answer 1

Answer: (A)

slower

Answer 2

{H_2SO_4 + \overset{\oplus }{{H}}$-> NO_2 + H$\overset{\Theta}{{S}}O_4 + H_2O }
{KHSO_4 -> K^{\oplus} + H\overset{\Theta}{{S}}O_4}
Due to common ion effect backward reaction will take place so the formation ${NO^{+}_{2}}$ decrease so nitration process will become slower.