Solveeit Logo

Question

Mathematics Question on Three Dimensional Geometry

Consider the lines L1 and L2 defined by
L1:x2+y1=0L_1: x\sqrt{2} + y - 1 = 0and L2:x2y+1=0L_2: x\sqrt{2} - y + 1 = 0
For a fixed constant λ, let C be the locus of a point P such that the product of the distance of P from L1 and the distance of P from L2 is λ2. The line y=2x+1y = 2x + 1 meets C at two points R and S, where the distance between R and S is 270.\sqrt{270}.
Let the perpendicular bisector of RS meet C at two distinct points R’ and S’. Let D be the square of the distance between R’ and S’.