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Question

Physics Question on Semiconductor electronics: materials, devices and simple circuits

Consider the junction diode as ideal. The value of current flowing through ABAB is :

A

10−2A10^{-2} A

B

10−1A10^{-1} A

C

10−3A10^{-3} A

D

0A 0 A

Answer

10−2A10^{-2} A

Explanation

Solution

Since diode is in forward bias i=ΔVR=4−(−6)1×103=10103=10−2Ai = \frac{\Delta V}{R} = \frac{4 - (-6)}{1 \times 10^{3}} = \frac{10}{10^3} = 10^{-2} A