Question
Question: Consider the given reaction What is the correct explanation for the reaction?  The product is formed due to nucleophilic substitution
B) The product is formed according to Sayzteff rule
C) Conjugated double bond product is formed due to higher stability because of resonance stabilization.
D) (CH3)3CO− is better leaving group
Solution
According to Saytzeff rule "In dehydrohalogenation reactions, the preferred product is that alkene which has the greater number of alkyl groups attached to the doubly bonded carbon atoms." For example: The dehydrohalogenation of 2-bromobutane yields two products 1-butene and 2-butene.
Complete answer:
We will look at the following question.
The dissociation of an acid H–A to give H+ and A– . The species A– is the conjugate base of HA. It accepts a pair of electrons from the H-A bond. It’s a base acting in reverse. The more stable A- is, the greater the equilibrium constant will be that favors dissociation to give A- .This turns out to be the very definition of acidity! The negative log of the equilibrium constant is the familiar pKa. These are the conjugate bases of strong acids. The stronger the acid, the weaker the conjugate base.
Option A) this is an incorrect option as this reaction is not a nucleophilic reaction.
Option B) this is an incorrect option as the major product is not the Saytzeff rule.
Option C) this is an incorrect option as conjugated double bond products are formed due to higher stability because of resonance stabilization.
Option D) this is a correct option.
Note: We need to know that in other words pKa is a direct measurement of how “happy” and stable a lone pair of electrons is the very definition of what we should be looking for when trying to quantify leaving group ability. So it should be no surprise to find that very weak bases such as halide ions (I−,Br−,Cl−) water (H2O), and sulfonates such as p-toluene sulfonate (OTs) and methane sulfonate(OMs) are excellent leaving groups.