Question
Question: Consider the following statements : \({{S}_{1}}:\,{{N}_{2}}{{H}_{4}}\,is\,pyramidal\,about\,each\,...
Consider the following statements :
S1:N2H4ispyramidalabouteachNatom
S2:NH2OHispyramidalabouteachNatomandbentabouttheOatom
S3:CH3COClistrigonalaboutthecarbonatom(attachedtoOandCl)
Select the correct statement.
A.S1andS2only
B.S1andS3only
C.S2andS3only
D.S1,S2andS3
Solution
Before solving this question, we should first know about the structures of N2H4, NH2OHand CH3COCl then find out which of the above statements are true. N2H4is hydrazine, NH2OHis hydroxylamine, and CH3COCl is acetyl chloride.
Complete answer:
N2H4 is an inorganic compound known as Hydrazine is a simple pnictogen hydride that is very toxic but controlled by a solution. It is a colorless liquid that is flammable and has an odor like ammonia. Polymer foams are prepared with the help of it. They are used as a precursor in pharmaceuticals, in numerous rocket fuels.
As we can see in this structure, N2H4is pyramidal about each N atom.
NH2OH is an inorganic compound known as hydroxylamine. It is a pure material that is unstable crystalline and is white. It is used as an aqueous solution. It is also used in the preparation of oximes.
As we can see in this structure, NH2OH Pyramidal about each N atom and bent about the O atom.
CH3COClis an organic compound known as acetyl chloride, a derivative of acetic acid. It comes under the category of acyl halides. It is a volatile liquid that is colorless and corrosive.
As we can see in this structure, CH3COCl is Trigonal about the carbon atom.
So, Option (D) S1,S2andS3 is correct.
Note:
Uses of –
N2H4– Cancer research, medicines, water boilers, inhibitors.
NH2OH- Purification of aldehydes and ketones, antioxidant for fatty acids.
CH3COCl- Dyes, Organic synthesis, quantitative analysis.