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Question

Question: Consider the following statements: \[\begin{aligned} & {{S}_{1}}=-8=2i\times 4i=\sqrt{-4}\time...

Consider the following statements:

& {{S}_{1}}=-8=2i\times 4i=\sqrt{-4}\times \sqrt{-16} \\\ & {{S}_{2}}:\sqrt{\left( -4 \right)}\times \sqrt{\left( -16 \right)}=\sqrt{\left( -4 \right)\times \left( -16 \right)} \\\ & {{S}_{3}}:\sqrt{\left( -4 \right)\times \left( -16 \right)}=\sqrt{64} \\\ & {{S}_{4}}:\sqrt{64}=8 \\\ \end{aligned}$$ Of these statements the incorrect one is, (a) $${{S}_{1}}$$ only (b) $${{S}_{2}}$$ only (c) $${{S}_{3}}$$ only (d) None of these
Explanation

Solution

Hint: First consider, 4×16\sqrt{-4}\times \sqrt{-16}. Try to find the answer using the mathematical form a×b=ab\sqrt{a}\times \sqrt{b}=\sqrt{ab} and by using complex form taking 1=i\sqrt{-1}=i. Thus, compare the 4 statements and find the wrong one.

Complete step-by-step answer:
We have been given 4 statements, from which we need to find which all are correct and which is wrong.
Thus let us first find the value of 4×16\sqrt{-4}\times \sqrt{-16}.
We all know that, a×b=ab\sqrt{a}\times \sqrt{b}=\sqrt{ab}.
But this mathematical equation holds true only and only when at least one of them is non – negative.
Here we have been given two negative numbers, which are (-4) and (-16). None of them are non – negative. Thus we can’t apply the rule or mathematical equations.
4×16=+64=±8\therefore \sqrt{-4}\times \sqrt{-16}=\sqrt{+64}=\pm 8, but this won’t give us the proper answer.
We know that, 1=i\sqrt{-1}=i.
4=(1)×4=2i\sqrt{-4}=\sqrt{\left( -1 \right)\times 4}=2i
Similarly, 16=(1)×16=4i\sqrt{-16}=\sqrt{\left( -1 \right)\times 16}=4i.
Thus, 4×16=2i×4i\sqrt{-4}\times \sqrt{-16}=2i\times 4i \left\\{ \because {{i}^{2}}=-1 \right\\}
4×16=8i2=8×(1)=8\sqrt{-4}\times \sqrt{-16}=8{{i}^{2}}=8\times \left( -1 \right)=-8
Thus, 4×16=8\sqrt{-4}\times \sqrt{-16}=-8.
Thus the correct answer for this expression of complex numbers is (-8).
Now let us look into S1:8=2i×4i=4×16{{S}_{1}}:-8=2i\times 4i=\sqrt{-4}\times \sqrt{-16}, now this is equal to the mathematical equation, a×b=ab\sqrt{a}\times \sqrt{b}=\sqrt{ab}. Thus S2{{S}_{2}} is also correct.
S3:(4)×(16)=64{{S}_{3}}:\sqrt{\left( -4 \right)\times \left( -16 \right)}=\sqrt{64}, which is also a correct statement.
Now let us look into S4:64=8{{S}_{4}}:\sqrt{64}=8, which is wrong.
64=±8\sqrt{64}=\pm 8
Thus out of the 4 statements S4{{S}_{4}} is wrong.
\therefore Option (d) is the correct answer.

Note: The reason why most say the answer is only (-8) is because, 1\sqrt{-1} is considered to be i, which isn’t a complete answer. Since every number in the complex plane must have exactly 2 distincting roots. We can say that both 8 and -8 could satisfy the equation.