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Question: Consider the following statements. (A) The coefficient of linear expansion has dimension \( {{K}^{...

Consider the following statements.
(A) The coefficient of linear expansion has dimension K1{{K}^{-1}}
(B) The coefficient of volume expansion has dimension K1{{K}^{-1}}
A. both A and B are correct
B. A is correct but B is wrong
C. B is correct but A is wrong
D. both A and B are wrong

Explanation

Solution

The unit for coefficient of linear expansion is to be found first. And also the unit of coefficient of volume of expansion should be found then. Check whether the units are matched to K1{{K}^{-1}} . These all will help us to find out the correct answer for this question.

Complete step-by-step answer:
First of all the coefficient of linear expansion is given by the equation,
α=ΔllΔt\alpha =\dfrac{\Delta l}{l\Delta t}
Where ll the initial length of the rod is, Δl\Delta l is the change in length of the rod and Δt\Delta t is the difference in the temperature.
Let us take the initial length of the rod as 1m1m .
That is,
l=1ml=1m
Change in length of the rod is can be taken as,
Δl=1m\Delta l=1m
And also change in temperature can be taken as,
Δt=1K\Delta t=1K
Substituting this values in the equation will give,
α=1m1m×1K=1K1\alpha =\dfrac{1m}{1m\times 1K}=1{{K}^{-1}}
Therefore the first statement is correct.
Now let us check the second statement.
The coefficient of volume expansion can be given by the equation,
γ=ΔVVΔt\gamma =\dfrac{\Delta V}{V\Delta t}
Where γ\gamma the coefficient of volume expansion is, ΔV\Delta V is the change in volume, VV is the initial volume and Δt\Delta t is the change in temperature.
Let us take all these parameters as unity,
Δt=1K\Delta t=1K
ΔV=1m3\Delta V=1{{m}^{3}}
V=1m3V=1{{m}^{3}}
Therefore the coefficient of volume expansion is given as,
γ=1m31m3×1K\gamma =\dfrac{1{{m}^{3}}}{1{{m}^{3}}\times 1K}
Simplifying the equation will give,
γ=K1\gamma ={{K}^{-1}}
Therefore the second statement is also correct. Hence we can conclude that the both statements are correct.

So, the correct answer is “Option A”.

Note: The ratio of the increase in length to the original length for 1 degree rise in the temperature is known as the coefficient of linear expansion. And also the ratio of increase in volume to the initial volume for 1 degree rise in temperature is known as the coefficient of volume expansion. The larger is the coefficient for a material, the more is the expansion per degree temperature rise.