Solveeit Logo
Login

Question

Chemistry Question on Chemical bonding and molecular structure

Consider the following species : CN+,CN−,NOCN^{+} , CN^{-} , NO and CNCN Which one of these will have the highest bond order ?

A

CNCN

B

NONO

C

CN+ CN^{+}

D

CN−CN^{-}

Answer

CN−CN^{-}

Explanation

Solution

NO:(σ1s)2,(σ∗1s)2,(σ2s)2,(σ∗2s)2,(σ2pz)2NO :(\sigma 1 s )^{2},\left(\sigma^{*} 1 s \right)^{2},(\sigma 2 s )^{2},\left(\sigma^{*} 2 s \right)^{2},\left(\sigma 2 p _{ z }\right)^{2}
(π2px)2=(π2py)2,(π∗2px)1=(π22py)0\left(\pi 2 p _{ x }\right)^{2}=\left(\pi 2 p _{ y }\right)^{2},\left(\pi^{*} 2 p _{ x }\right)^{1}=\left(\pi^{2} 2 p _{ y }\right)^{0}
BO=10−52=2.5BO =\frac{10-5}{2}=2.5
CN−:(σ1s)2,(σ∗1s)2,(σ2s)2,(σ∗2s)2,(π2px)2CN ^{-}:(\sigma 1 s )^{2},\left(\sigma^{*} 1 s \right)^{2},(\sigma 2 s )^{2},\left(\sigma^{*} 2 s \right)^{2},\left(\pi 2 p _{ x }\right)^{2}
=(π2py)2,(σ2zz)2=\left(\pi 2 p _{ y }\right)^{2},\left(\sigma 2 z _{ z }\right)^{2}
BO=10−42=3BO =\frac{10-4}{2}=3
CN:(σ1s)2,(σ∗1s)2,(σ2s)2,(σ∗2s)2,(π2px)2CN :(\sigma 1 s )^{2},\left(\sigma^{*} 1 s \right)^{2},(\sigma 2 s )^{2},\left(\sigma^{*} 2 s \right)^{2},\left(\pi 2 p _{ x }\right)^{2}
=(π2py)2,(σ2pz)1=\left(\pi 2 p _{ y }\right)^{2},\left(\sigma 2 p _{ z }\right)^{1}
BO=9−42=2.5BO =\frac{9-4}{2}=2.5
CN+:(σ1s)2,(σ∗1s)2,(σ2s)2,(σ∗2s)2,(π2px)2CN ^{+}:(\sigma 1 s )^{2},\left(\sigma^{*} 1 s \right)^{2},(\sigma 2 s )^{2},\left(\sigma^{*} 2 s \right)^{2},\left(\pi 2 p _{ x }\right)^{2}
=(π2py)2=\left(\pi 2 p _{ y }\right)^{2}
BO=8−42=2BO =\frac{8-4}{2}=2