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Question: Consider the following reactions at 300 K. A\(\rightarrow\)B (uncatalysed reaction) \(A\overset{\...

Consider the following reactions at 300 K.

A\rightarrowB

(uncatalysed reaction)

AcatalystBA\overset{\quad catalyst\quad}{\rightarrow}B (catalyst reaction)

The activation energy is lowered by 8.314 KJ mol–1 for the catalysed reaction. How many times the rate of this catalysed reaction greater than that of uncatalysedreaction ? (Given e3.33 = 28)

A

15 times

B

38 times

C

22 times

D

28 times

Answer

28 times

Explanation

Solution

A ® B (uncatalysed reaction) ABA \rightarrow B

(catalyst reaction)

K = A e-Ea/RT\text{K = A }\text{e}^{\text{-Ea/RT}}

Kcat. = Ae-Ea(cat)/RTK_{\text{cat}}\text{. = A}e^{\text{-Ea}\left( \text{cat} \right)/RT}

KcatK=e8.314×1038.314×300=e3.33=28times\frac{K_{cat}}{K} = e^{\frac{8.314 \times 10^{3}}{8.314 \times 300}} = e^{3.33} = 28times