Question
Question: Consider the following reactions at 300 K. A\(\rightarrow\)B (uncatalysed reaction) \(A\overset{\...
Consider the following reactions at 300 K.
A→B
(uncatalysed reaction)
A→catalystB (catalyst reaction)
The activation energy is lowered by 8.314 KJ mol–1 for the catalysed reaction. How many times the rate of this catalysed reaction greater than that of uncatalysedreaction ? (Given e3.33 = 28)
A
15 times
B
38 times
C
22 times
D
28 times
Answer
28 times
Explanation
Solution
A ® B (uncatalysed reaction) A→B

(catalyst reaction)
K = A e-Ea/RT
Kcat. = Ae-Ea(cat)/RT
KKcat=e8.314×3008.314×103=e3.33=28times