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Question: Consider the following reactions: (a).\({\left( {C{H_3}} \right)_3}CCH\left( {OH} \right)C{H_3}\xr...

Consider the following reactions:
(a).(CH3)3CCH(OH)CH3→conc.H2SO4{\left( {C{H_3}} \right)_3}CCH\left( {OH} \right)C{H_3}\xrightarrow{{conc.{H_2}S{O_4}}}
(b).(CH3)3CCH(OH)CH3→conc.H2SO4{\left( {C{H_3}} \right)_3}CCH\left( {OH} \right)C{H_3}\xrightarrow{{conc.{H_2}S{O_4}}}
(c).(CH3)2CHCH(Br)CH3→(CH3)3CO−K+{\left( {C{H_3}} \right)_2}CHCH\left( {Br} \right)C{H_3}\xrightarrow{{{{\left( {C{H_3}} \right)}_3}C{O^ - }{K^ + }}}
(d).(CH3)2C(OH)CH2CHO→Δ{\left( {C{H_3}} \right)_2}C\left( {OH} \right)C{H_2}CHO\xrightarrow{\Delta }
Which of these reaction(s) will not produce the Saytzeff product?
(A). (c) only
(B).(b) and (d)
(C).(d) only
(D). (a), (c) and (d).

Explanation

Solution

We need to realize that the Saytzeff rule is ordinarily utilized in natural science. It helps in the expectation of the better return alkene when a specific compound goes through end response. It is additionally known by the name Saytzeff-Hofmann rule.

Complete answer:
We have to know that, Saytzeff's Rule is additionally called Zaitsev's standard, Saytzev's standard or Z-rule. A Russian scientific expert, Alexander Zaitsev dissected distinctive disposal responses and noticed an overall example in the subsequent alkenes. In view of this examination, Zaitsev expressed that steady alkene is framed when the expulsion of hydrogen from β-carbon has a low number of hydrogen substituents.
During disposal reactions, Saytzeff's Rule comes into the picture. The most subbed item would be the most steady and most favored one. This standard doesn't make speculations regarding the item stereochemistry, yet just the regiochemistry of the disposal reaction.
Elimination reactions of some alkyl halides and liquor will bring about various alkenes and Saytzeff's Rule is utilized to anticipate the significant item. The major and minor items are anticipated depending on the quantity of alkyl bunches appended to the alkene.
Therefore,
The Saytzeff rule is not obeyed by (c). Because it is not a Saytzeff product.
The reaction of (c) has to be given,

Remaining options are to produce the Saytzeff product.

Hence, the correct option is (A) (c) only.

Note:
States that if beyond what one alkene can be shaped during dehalogenation by a disposal response, the more steady alkene is the significant item. By and large, the compound that has an all the more profoundly subbed C=C twofold bond is more steady.