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Question

Chemistry Question on Oxidation Number

Consider the following reaction: 6NaOH+3cl25Nacl+A+3H2O6NaOH +3cl_{2} \to5Nacl +A+3H_{2}O What is the oxidation number of chlorine in A?

A

5

B

-1

C

3

D

1

Answer

5

Explanation

Solution

The correct answer is A:5
Balance the equation 6NaOH+3cl25NaCl+A+3H2O6NaOH+3cl_{2} \to5NaCl +A+3H_{2}O
to get, 6NaOH+3cl25NaCl+NaClO3+3H2O6NaOH+3cl_{2} \to5NaCl +NaClO_{3}+3H_{2}O
\therefore A is NaClO3,NaClO_{3} , where Cl is in +5 oxidation state