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Chemistry Question on Stoichiometry and Stoichiometric Calculations

Consider the following reaction:3PbCl2+2(NH4)3PO4→Pb3(PO4)2+6NH4Cl3\text{PbCl}_2 + 2(\text{NH}_4)_3\text{PO}_4 \rightarrow \text{Pb}_3(\text{PO}_4)_2 + 6\text{NH}_4\text{Cl}If 72 mmol of PbCl2_2 is mixed with 50 mmol of (NH4\text{NH}_4)3_3PO4_4, then the amount of Pb3(PO4)2\text{Pb}_3(\text{PO}_4)_2 formed is ______ mmol (nearest integer).

Answer

Limiting reagent is PbCl2.

Amount of Pb3(PO4)2 formed:

mmol of Pb3(PO4)2=mmol of PbCl2 reacted3=24 mmol\text{mmol of Pb}_3(\text{PO}_4)_2 = \frac{\text{mmol of PbCl}_2 \text{ reacted}}{3} = 24 \text{ mmol}