Question

Consider the following reaction:
${2HSO_4^ −}_{(aq)}\xrightarrow[(2)Hydrolysis]{(1)Electrolysis} 2HSO_4^− + 2H^+ + A$
The dihedral angle in product A in its solid phase at 110 K is :

• A. 104°
• B. 111.5°
• C. 90.2°
• D. 111.0°

Answer 1

Answer: (C)

90.2°

Answer 2

A should be H2O2
Structure of H2O2 is solid phase

Dihedral angle = 90.2°