Question

Consider the following radioactive decay process ${ }_{84}^{218} A \xrightarrow{\alpha} A_1 \xrightarrow{\beta^{-}}A_2 \xrightarrow{\gamma} A_3 \xrightarrow{\alpha} A_4 \xrightarrow{\beta^{+}} A_5 \xrightarrow{\gamma}A_6$ The mass number and the atomic number of $A_6$ are given by:

• A. 211 and 80
• B. 210 and 80
• C. 210 and 82
• D. 210 and 84

Answer 1

Answer: (B)

210 and 80

Answer 2

The correct answer is (B) : 210 and 80
84218​A⟶α​82214​A1​⟶β−​83214​A2​⟶γ​83214​A3​
83214​A3​⟶α​81210​A4​⟶β+​80210​A5​⟶γ​80210​A6​