Question

Consider the following processes : $\Delta H (kJ / mol)$ ½ A → B + 150 3B → 2C + D -125 E + A → 2D +350 For B + D → E + 2C, ΔH will be-

• A. 325 kJ/mol
• B. 525 kJ/mol
• C. -175 kJ.mol
• D. -325 kJ/mol

Answer 1

Answer: (C)

-175 kJ.mol

Answer 2

$2(i) - (iii) + (ii)$
$\Delta H = 2(150) - 350 - 125$
$= - 175 \, kJ / mol$