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Question: Consider the following liquid – vapour equilibrium \[Liquid \leftrightharpoons Vapour\]. Which of ...

Consider the following liquid – vapour equilibrium LiquidVapourLiquid \leftrightharpoons Vapour. Which of the following relations is correct?
A. dlnGdT2ΔHVRT2\dfrac{{d\ln G}}{{d{T^2}}} \Rightarrow \dfrac{{\Delta {H_V}}}{{R{T^2}}}
B. dlnPdTΔHVRT\dfrac{{d\ln P}}{{dT}} \Rightarrow - \dfrac{{\Delta {H_V}}}{{RT}}
C. dlnPdT2ΔHVT2\dfrac{{d\ln P}}{{d{T^2}}} \Rightarrow - \dfrac{{\Delta {H_V}}}{{{T^2}}}
D. dlnPdTΔHVRT2\dfrac{{d\ln P}}{{dT}} \Rightarrow \dfrac{{\Delta {H_V}}}{{R{T^2}}}

Explanation

Solution

This given condition is for Clausius - Clapeyron's equation. The equilibrium between water and water vapor depends upon the temperature of the system.

Step by step answer: According to our question, correct answer is dlnPdTΔHVRT2\dfrac{{d\ln P}}{{dT}} \Rightarrow \dfrac{{\Delta {H_V}}}{{R{T^2}}} as this equation is Clausius - Clapeyron's. The rate at which the regular logarithm of the fume weight of a fluid changes with temperature is dictated by the molar enthalpy of vaporization of the fluid, the ideal gas steady, and the temperature of the system.

Clausius - Clapeyron's equation:
If the temperature expands the immersion weight of the water fume increases. The pace of increment in fume pressure per unit increment in temperature is given by Clausius-Clapeyron's condition. Let PP be the saturation vapor pressure and TT the temperature. The Clausius-Clapeyron’s condition for the balance among fluid and fume is at that point
dPdTLT(VVV1)\dfrac{{dP}}{{dT}} \Rightarrow \dfrac{L}{{T({V_V} - {V_1})}}
WhereLL is the latent heat of evaporation, and VV{V_V}andV1{V_1} are the specific volumes at temperature TT of the vapor and liquid phases, respectively.
The ideal gas condition applies to the fume; i.e.
pVVRTp{V_V} \Rightarrow RT
And hence
VVRTp{V_V} \Rightarrow \dfrac{{RT}}{p}
Where RRis the universal gas constant.
It is critical to not utilize the Clausius-Clapeyron’s condition for the strong to fluid change. That requires the use of the more general Clapeyron’s rquation
dPdTΔHTΔV\dfrac{{dP}}{{dT}} \Rightarrow \dfrac{{\Delta H}}{{T\Delta V}}
Where ΔH\Delta H and ΔV\Delta V is the molar change in enthalpy (the enthalpy of fusion in this case) and volume respectively between the two phases in the transition.

Hence the correct option is (D).

Note: LiquidVapourLiquid \leftrightharpoons Vapour equilibrium states that when liquid is heated, it converts into vapour but on cooling, it further converts into liquid, which is derived by Clausius - Clapeyron's equation.