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Question

Question: Consider the following expression and find the value of ‘x’: \[8{{x}^{\dfrac{3}{2n}}}-8{{x}^{-\dfrac...

Consider the following expression and find the value of ‘x’: 8x32n8x32n=638{{x}^{\dfrac{3}{2n}}}-8{{x}^{-\dfrac{3}{2n}}}=63
This question has multiple correct options.
A. 22n{{2}^{2n}}
B. 212n{{2}^{\dfrac{1}{2n}}}
C. 23n{{2}^{3n}}
D. 213n{{2}^{\dfrac{1}{3n}}}

Explanation

Solution

First consider the x32n=y{{x}^{\dfrac{3}{2n}}}=yby replacing this value by y then we will get quadratic equation in y. solve the quadratic equation in y then we will get values of y and again replace y by corresponding value in x then we will get the value of x.

Complete step by step answer:
Given that 8x32n8x32n=638{{x}^{\dfrac{3}{2n}}}-8{{x}^{-\dfrac{3}{2n}}}=63
For this problem we have to find the value of x
Let us consider x32n=y{{x}^{\dfrac{3}{2n}}}=y
Replacing that value by x then we will get the equation as follows
8y8y1=638y-8{{y}^{-1}}=63
8y8y=638y-\dfrac{8}{y}=63
8y28=63y8{{y}^{2}}-8=63y
8y263y8=08{{y}^{2}}-63y-8=0. . . . . . . . . . . (1)
Now solve the above equation quadratic equation then we will get values of y as follows
8y264y+y8=08{{y}^{2}}-64y+y-8=0
8y(y8)+1(y8)=08y\left( y-8 \right)+1\left( y-8 \right)=0
(y8)(8y+1)=0\left( y-8 \right)\left( 8y+1 \right)=0
y=8,y=18y=8,y=-\dfrac{1}{8}
So the obtained values of y is y=8,y=18y=8,y=-\dfrac{1}{8}. . . . . . . . . . (2)
First we have considered that x32n=y{{x}^{\dfrac{3}{2n}}}=y
Let us take y=8y=8
x32n=8{{x}^{\dfrac{3}{2n}}}=8
8 can be written 2 to the power of 3
x32n=23{{x}^{\dfrac{3}{2n}}}={{2}^{3}}
x=(23)2n3x={{({{2}^{3}})}^{\dfrac{2n}{3}}}
x=22nx={{2}^{2n}}. . . . . . . . . . . (3)
So the obtained value of x for y=8 is x=22nx={{2}^{2n}}
Let us take y=18y=-\dfrac{1}{8}
18\dfrac{1}{8}can be 2 to the power of -3
x32n=18{{x}^{\dfrac{3}{2n}}}=-\dfrac{1}{8}
x32n=23{{x}^{\dfrac{3}{2n}}}=-{{2}^{-3}}
x=(23)2n3x={{(-{{2}^{-3}})}^{\dfrac{2n}{3}}}
x=(2)2nx={{\left( -2 \right)}^{-2n}}
x=(2)2nx={{\left( 2 \right)}^{-2n}}
x=(2)12nx={{\left( 2 \right)}^{\dfrac{1}{2n}}}. . . . . . . . . . . (4)
So the obtained value of x for y=18y=-\dfrac{1}{8}is x=(2)12nx={{\left( 2 \right)}^{\dfrac{1}{2n}}}
So the correct option is option (A), (B).

Note:
In this problem we will get quadratic in y so we can get two values of y , we have considered a corresponding value in x by y so we also get two of values of x. we used factorization method to solve quadratic equation in y we can get the two values of y either by factorization method or using formula.