Question
Question: Consider the following expression and find the value of ‘x’: \[8{{x}^{\dfrac{3}{2n}}}-8{{x}^{-\dfrac...
Consider the following expression and find the value of ‘x’: 8x2n3−8x−2n3=63
This question has multiple correct options.
A. 22n
B. 22n1
C. 23n
D. 23n1
Solution
First consider the x2n3=yby replacing this value by y then we will get quadratic equation in y. solve the quadratic equation in y then we will get values of y and again replace y by corresponding value in x then we will get the value of x.
Complete step by step answer:
Given that 8x2n3−8x−2n3=63
For this problem we have to find the value of x
Let us consider x2n3=y
Replacing that value by x then we will get the equation as follows
8y−8y−1=63
8y−y8=63
8y2−8=63y
8y2−63y−8=0. . . . . . . . . . . (1)
Now solve the above equation quadratic equation then we will get values of y as follows
8y2−64y+y−8=0
8y(y−8)+1(y−8)=0
(y−8)(8y+1)=0
y=8,y=−81
So the obtained values of y is y=8,y=−81. . . . . . . . . . (2)
First we have considered that x2n3=y
Let us take y=8
x2n3=8
8 can be written 2 to the power of 3
x2n3=23
x=(23)32n
x=22n. . . . . . . . . . . (3)
So the obtained value of x for y=8 is x=22n
Let us take y=−81
81can be 2 to the power of -3
x2n3=−81
x2n3=−2−3
x=(−2−3)32n
x=(−2)−2n
x=(2)−2n
x=(2)2n1. . . . . . . . . . . (4)
So the obtained value of x for y=−81is x=(2)2n1
So the correct option is option (A), (B).
Note:
In this problem we will get quadratic in y so we can get two values of y , we have considered a corresponding value in x by y so we also get two of values of x. we used factorization method to solve quadratic equation in y we can get the two values of y either by factorization method or using formula.