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Question: The heat of formation of benzene is __________ kJmol$^{-1}$. (Nearest integer)...

The heat of formation of benzene is __________ kJmol1^{-1}. (Nearest integer)

Answer

48

Explanation

Solution

The balanced combustion equation for benzene is C6_6H6_6(l) + 152\frac{15}{2}O2_2(g) \rightarrow 6CO2_2(g) + 3H2_2O(l). Using the thermochemical relation ΔHcombustion=ΔHf(products)ΔHf(reactants)\Delta H_{combustion} = \sum \Delta H_f(\text{products}) - \sum \Delta H_f(\text{reactants}): 3267.0 kJ/mol=[6×(393.5)+3×(286.0)][ΔHf(C6H6)+152×0]-3267.0 \text{ kJ/mol} = [6 \times (-393.5) + 3 \times (-286.0)] - [\Delta H_f(\text{C}_6\text{H}_6) + \frac{15}{2} \times 0] 3267.0=[2361.0858.0]ΔHf(C6H6)-3267.0 = [-2361.0 - 858.0] - \Delta H_f(\text{C}_6\text{H}_6) 3267.0=3219.0ΔHf(C6H6)-3267.0 = -3219.0 - \Delta H_f(\text{C}_6\text{H}_6) ΔHf(C6H6)=3219.0+3267.0=48.0 kJ/mol\Delta H_f(\text{C}_6\text{H}_6) = -3219.0 + 3267.0 = 48.0 \text{ kJ/mol}.