Question

Consider the following carbocations : I. $Cl_3 \overset{+}C$ II. $Cl_{2} \overset{+} {C}H$ III. $Cl \overset{+} {C}H_{2}$ IV. $\overset{+} {C}H_{3}$ The stability sequence follows the order

• A. IV < I < III < II
• B. I < II < III < IV
• C. II < III < IV < I
• D. III < I < II < IV

Answer 1

Answer: (B)

I < II < III < IV

Answer 2

Electron withdrawing groups like $?NO_2$, $? X$ etc., decrease the stability of carbonium ion. So, the stability order is $Cl_3C^+ < Cl_2$ $\overset{+}{C}H < Cl \overset{+}{C}H_2 < \overset{+}{C}H_3$