Question

Consider the following bromides : The correct order of $S_N1$ reactivity is

• A. $B > C > A$
• B. $B > A > C$
• C. $C > B > A$
• D. $A > B > C$

Answer 1

Answer: (A)

$B > C > A$

Answer 2

$S_N1$ proceeds via carbocation intermediate, the most stable one forming the product faster. Hence reactivity order for $A,\, B, \,C$ depends on stability of carbocation created.