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Question

Chemistry Question on Electrochemical Cells

Consider the following 4 electrodes
A : Ag+ (0.0001 M)/Ag(s) ; B : Ag+ (0.1 M) / Ag(s)
C : Ag+ (0.01 M)/Ag(s) ; D : Ag+ (0.001 M) / Ag(s); EAg+/AgE^{\degree}_{Ag^{+/Ag}}=+ 0.80 V
Then reduction potential in volts of the electrodes in the order

A

B > C > D > A

B

C > D > A > B

C

A > D > C > B

D

A > B > C > D

Answer

B > C > D > A

Explanation

Solution

The correct answer is (A) : B > C > D > A.