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Question: Consider the fission reaction <sub>92</sub>U<sup>236</sup>¾® X<sup>117</sup> + Y<sup>117</sup> + <s...

Consider the fission reaction

92U236¾® X117 + Y117 + 0n1 + 0n1

i.e. two nuclei of same mass number 117 are formed plus two neutrons. The binding energy per nucleon of X and Y is 8.5 MeV whereas of U236 is 7.6 MeV. The total energy liberated will be about-

A

2 MeV

B

20 MeV

C

200 MeV

D

2000 MeV

Answer

200 MeV

Explanation

Solution

Q = B.Ef – B. Ei

= (2 × 117 × 8.5 – 236 × 7.6) MeV

= (1989 – 1793.6) MeV \simeq 200 MeV