Question
Question: Consider the fission reaction <sub>92</sub>U<sup>236</sup>¾® X<sup>117</sup> + Y<sup>117</sup> + <s...
Consider the fission reaction
92U236¾® X117 + Y117 + 0n1 + 0n1
i.e. two nuclei of same mass number 117 are formed plus two neutrons. The binding energy per nucleon of X and Y is 8.5 MeV whereas of U236 is 7.6 MeV. The total energy liberated will be about-
A
2 MeV
B
20 MeV
C
200 MeV
D
2000 MeV
Answer
200 MeV
Explanation
Solution
Q = B.Ef – B. Ei
= (2 × 117 × 8.5 – 236 × 7.6) MeV
= (1989 – 1793.6) MeV ≃ 200 MeV