Question

Consider the equilibrium set up: ${2H2_{(g)} +CO_{(g)} <=> CH3OH_{(g)}}$ What will be the effect of the following on the equilibrium of the reaction? (i) Addition of $H_2$ (ii) Addition of $CH_3OH$ (iii) Removal of $CO$ (iv) Removal of $CH_3OH$

• A. a
• B. b
• C. c
• D. d

Answer 1

Answer: (A)

a

Answer 2

(i) Increase in concentration of reactants favours forward reaction. (ii) Increase in concentration of products favours backward reaction. (iii) Removal of $CO$ will favour backward reaction (decrease in concentration of reactants). (iv) Removal of $CH_3OH$ will favour forward reaction (increase in concentration of products).