Question

Consider the ellipse $\frac{x^2}{9}+\frac{y^2}{4}=1$. Let S (p, q) be a point in the first quadrant such that $\frac{p^2}{9}+\frac{q^2}{4}>1$. Two tangents are drawn from S to the ellipse, of which one meets the ellipse at one end point of the minor axis and the other meets the ellipse at a point T in the fourth quadrant. Let R be the vertex of the ellipse with positive x-coordinate and Obe the center of the ellipse. If the area of the triangle △ORT is $\frac{3}{2}$ , then which of the following options is correct ?

• A. $q=2,p=3\sqrt3$
• B. $q=2,p=4\sqrt3$
• C. $0.5m,-5kg \ \frac{m}{s}$
• D. $-1m,5kg \ \frac{m}{s}$

Answer 1

Answer: (A)

$q=2,p=3\sqrt3$

Answer 2

The correct option is (A):$q=2,p=3\sqrt3$.