Question

Consider the circuit shown in the figure. Find the charge on capacitor C between A and D in a steady state.

• A. $C_\epsilon$
• B. $\frac{C_\epsilon}{2}$
• C. $\frac{C_\epsilon}{3}$
• D. zero

Answer 1

Answer: (D)

zero

Answer 2

The correct answer is d. Zero
Explanation: A capacitor blocks the DC steady state i.e. a capacitor behaves as an open circuit in a steady state. Hence no current will flow through the capacitor. Therefore, the potential difference between A and D is, V = 0

The capacitance of a capacitor is given by, C = qV

⇒ C = 0