Question

Consider the change in oxidation state of Bromine corresponding to different emf values as shown in the diagram below : is Then the species undergoing disproportionation is

• A. $HBrO$
• B. $BrO^{-}_3$
• C. $Br_2$
• D. $BrO^{-}_4$

Answer 1

Answer: (A)

$HBrO$

Answer 2

$\overset{+1}{HBrO} \longrightarrow B\overset{0}{r _{2}}, E _{ HBrO / Br _{2}}^{0}=1.595\, V$
$\overset{+1}{HBrO} \longrightarrow \overset{+5}{Br}O _{3}^{-}, E _{ BrO _{3}^{-} / HBrO }^{ O }=1.5 \,V$
$E _{\text {cell }}^{\circ}$ for the disproportionation of HBrO,

$E_{\text {cell }}^{\circ}=E_{ HBrO / Br _{2}}^{\circ}-E_{ BrO _{3}^{-} / H B r O}^{\circ}$
$=1.595-1.5$
$=0.095\, V =+ ve$