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Physics Question on Thermodynamics

Consider one mole of helium gas enclosed in a container at initial pressure P1P_{1} and volume V1V_{1}. It expands isothermally to volume 4V14 V_{1}. After this, the gas expands adiabatically and its volume becomes 32V132 V _{1}. The work done by the gas during isothermal and adiabatic expansion processes are Wiso W_{\text {iso }} and WW respectively. If the ratio Wiso Wadia =fln2\frac{W_{\text {iso }}}{W_{\text {adia }}}=f \ln 2, then ff is ?

Answer

then ff is 1.78.\underline{1.78}.

Explanation

Solution

then ff is 1.78.\underline{1.78}.