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Question: Consider one He<sup>+</sup> ion in excited state (n = 5). Which of the following observations will h...

Consider one He+ ion in excited state (n = 5). Which of the following observations will hold true as per the Bohr's model–

A

10 emission spectral lines will be seen

B

The ionisation energy needed is less than 2eV

C

The longest emitted wavelength is less than 10/R

(R = Rydberg's constant)

D

The electronic separation from the centre of nucleus is more than 6 Å

Answer

The electronic separation from the centre of nucleus is more than 6 Å

Explanation

Solution

A multitude of He+ will produce 10 possible

emission lines. A single He+ can produce maximum

4 lines (not more)

5 ¾¾® 4 ¾¾® 3 ¾¾® 2 ¾¾® 1

En = – 13.6 z2n2\frac{z^{2}}{n^{2}} = – 13.6 × 2252\frac{2^{2}}{5^{2}} = – 13.6 × 425\frac{4}{25}

= – 2.176 eV

\ I.E = + 2.176 eV > 2eV

1λ=RZ2[1n121n22]\frac{1}{\lambda} = RZ^{2}\left\lbrack \frac{1}{n_{1}^{2}}–\frac{1}{n_{2}^{2}} \right\rbrack

1λ=R.4[142152]\frac{1}{\lambda} = R.4\left\lbrack \frac{1}{4^{2}}–\frac{1}{5^{2}} \right\rbrack

1λ=4R[916×25]\frac{1}{\lambda} = 4R\left\lbrack \frac{9}{16 \times 25} \right\rbrack

1λ=16×254×9×R=1009R>10R\frac{1}{\lambda} = \frac{16 \times 25}{4 \times 9 \times R} = \frac{100}{9R} > \frac{10}{R}rn = 0.53 ×n2Z=0.53×52Z\frac{n^{2}}{Z} = 0.53 \times \frac{5^{2}}{Z}

= 6.625 Å > 6°A