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Question

Chemistry Question on Chemical Kinetics

Consider an endothermic reaction XYX\, \to \,Y with the activation energies EbE_b and EfE_f for the backward and forward reactions respectively. In general :

A

there is no definite relation between EbE_b and EfE_f

B

Eb=EfE_b = E_f

C

Eb>EfE_b > E_f

D

Eb<EfE_b < E_f

Answer

Eb<EfE_b < E_f

Explanation

Solution

XYX\, \to \,Y is an endothermic reaction ΔH=+ve\Delta H = + ve EbE_b = energy of activation of backward reaction EfE_f = energy of activation of forward reaction ΔH\Delta H = heat of reaction Thus. \quad \quad Eb=EfE_b = E_f +ΔH\Delta H Thus \quad \quad Eb>EfE_b > E_f