Question

Consider an electron in the nth orbit of a hydrogen atom in the Bohr model. The circumference of the orbit can be expressed in terms of the de Broglie wavelength $\lambda$ of the electron as :

• A. (0.529) n$\lambda$
• B. $\sqrt{n}\lambda$
• C. (13.6) $\lambda$
• D. $n\lambda$

Answer 1

Answer: (D)

$n\lambda$

Answer 2

2$\pi r = n\lambda =$ circumference