Question

Consider an electron in the n^th orbit of a hydrogen atom in the Bohr model. The circumference of the orbit can be expressed in terms of the de Broglie wavelength $\lambda$of that electron as.

• A. $(0.259)\mspace{6mu} n\lambda$
• B. $\sqrt{n}\lambda$
• C. $(13.6)\mspace{6mu}\lambda$
• D. $n\lambda$

Answer 1

Answer: (D)

$n\lambda$

Answer 2

According to Bohr’s theory

$mvr = n\frac{h}{2\pi}$

⇒ Circumference $2\pi r = n\left( \frac{h}{mv} \right) = n\lambda$.